自ブクマから modulo使わずにfizzbuzz > (defun fizzbuzz-to (n) (do ((i 1 (1+ i)) (f 1 (if (<= 2 f) 0 (1+ f))) (b 1 (if (<= 4 b) 0 (1+ b))) (acc nil)) ((< n i) (nreverse acc)) (push (cond ((= f b 0) 'FizzBuzz) ((= f 0) 'Fizz ) ((= b 0) 'Buzz)…